Add solution #1710

Author: JoshCrozier

README.md

@@ -1,4 +1,4 @@
-# 1,492 LeetCode solutions in JavaScript
+# 1,493 LeetCode solutions in JavaScript
 
 [https://leetcodejavascript.com](https://leetcodejavascript.com)
 
@@ -1317,6 +1317,7 @@
 1705|[Maximum Number of Eaten Apples](./solutions/1705-maximum-number-of-eaten-apples.js)|Medium|
 1706|[Where Will the Ball Fall](./solutions/1706-where-will-the-ball-fall.js)|Medium|
 1707|[Maximum XOR With an Element From Array](./solutions/1707-maximum-xor-with-an-element-from-array.js)|Hard|
+1710|[Maximum Units on a Truck](./solutions/1710-maximum-units-on-a-truck.js)|Easy|
 1716|[Calculate Money in Leetcode Bank](./solutions/1716-calculate-money-in-leetcode-bank.js)|Easy|
 1718|[Construct the Lexicographically Largest Valid Sequence](./solutions/1718-construct-the-lexicographically-largest-valid-sequence.js)|Medium|
 1726|[Tuple with Same Product](./solutions/1726-tuple-with-same-product.js)|Medium|

solutions/1710-maximum-units-on-a-truck.js

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+/**
+ * 1710. Maximum Units on a Truck
+ * https://leetcode.com/problems/maximum-units-on-a-truck/
+ * Difficulty: Easy
+ *
+ * You are assigned to put some amount of boxes onto one truck. You are given a 2D array
+ * boxTypes, where boxTypes[i] = [numberOfBoxesi, numberOfUnitsPerBoxi]:
+ * - numberOfBoxesi is the number of boxes of type i.
+ * - numberOfUnitsPerBoxi is the number of units in each box of the type i.
+ *
+ * You are also given an integer truckSize, which is the maximum number of boxes that can be
+ * put on the truck. You can choose any boxes to put on the truck as long as the number of
+ * boxes does not exceed truckSize.
+ *
+ * Return the maximum total number of units that can be put on the truck.
+ */
+
+/**
+ * @param {number[][]} boxTypes
+ * @param {number} truckSize
+ * @return {number}
+ */
+var maximumUnits = function(boxTypes, truckSize) {
+  boxTypes.sort((a, b) => b[1] - a[1]);
+  let result = 0;
+  let remainingBoxes = truckSize;
+
+  for (const [count, units] of boxTypes) {
+    const boxesToTake = Math.min(count, remainingBoxes);
+    result += boxesToTake * units;
+    remainingBoxes -= boxesToTake;
+    if (remainingBoxes === 0) break;
+  }
+
+  return result;
+};