diff --git a/README.md b/README.md
index a795cb17..baec6d02 100644
--- a/README.md
+++ b/README.md
@@ -2674,6 +2674,7 @@
 3183|[The Number of Ways to Make the Sum](./solutions/3183-the-number-of-ways-to-make-the-sum.js)|Medium|
 3186|[Maximum Total Damage With Spell Casting](./solutions/3186-maximum-total-damage-with-spell-casting.js)|Medium|
 3189|[Minimum Moves to Get a Peaceful Board](./solutions/3189-minimum-moves-to-get-a-peaceful-board.js)|Medium|
+3190|[Find Minimum Operations to Make All Elements Divisible by Three](./solutions/3190-find-minimum-operations-to-make-all-elements-divisible-by-three.js)|Easy|
 3191|[Minimum Operations to Make Binary Array Elements Equal to One I](./solutions/3191-minimum-operations-to-make-binary-array-elements-equal-to-one-i.js)|Medium|
 3195|[Find the Minimum Area to Cover All Ones I](./solutions/3195-find-the-minimum-area-to-cover-all-ones-i.js)|Medium|
 3197|[Find the Minimum Area to Cover All Ones II](./solutions/3197-find-the-minimum-area-to-cover-all-ones-ii.js)|Hard|
@@ -2703,6 +2704,7 @@
 3306|[Count of Substrings Containing Every Vowel and K Consonants II](./solutions/3306-count-of-substrings-containing-every-vowel-and-k-consonants-ii.js)|Medium|
 3307|[Find the K-th Character in String Game II](./solutions/3307-find-the-k-th-character-in-string-game-ii.js)|Hard|
 3313|[Find the Last Marked Nodes in Tree](./solutions/3313-find-the-last-marked-nodes-in-tree.js)|Hard|
+3318|[Find X-Sum of All K-Long Subarrays I](./solutions/3318-find-x-sum-of-all-k-long-subarrays-i.js)|Easy|
 3323|[Minimize Connected Groups by Inserting Interval](./solutions/3323-minimize-connected-groups-by-inserting-interval.js)|Medium|
 3329|[Count Substrings With K-Frequency Characters II](./solutions/3329-count-substrings-with-k-frequency-characters-ii.js)|Hard|
 3330|[Find the Original Typed String I](./solutions/3330-find-the-original-typed-string-i.js)|Easy|
@@ -2776,6 +2778,7 @@
 3506|[Find Time Required to Eliminate Bacterial Strains](./solutions/3506-find-time-required-to-eliminate-bacterial-strains.js)|Hard|
 3508|[Implement Router](./solutions/3508-implement-router.js)|Medium|
 3511|[Make a Positive Array](./solutions/3511-make-a-positive-array.js)|Medium|
+3512|[Minimum Operations to Make Array Sum Divisible by K](./solutions/3512-minimum-operations-to-make-array-sum-divisible-by-k.js)|Easy|
 3516|[Find Closest Person](./solutions/3516-find-closest-person.js)|Easy|
 3520|[Minimum Threshold for Inversion Pairs Count](./solutions/3520-minimum-threshold-for-inversion-pairs-count.js)|Medium|
 3535|[Unit Conversion II](./solutions/3535-unit-conversion-ii.js)|Medium|
diff --git a/solutions/3190-find-minimum-operations-to-make-all-elements-divisible-by-three.js b/solutions/3190-find-minimum-operations-to-make-all-elements-divisible-by-three.js
new file mode 100644
index 00000000..24effff2
--- /dev/null
+++ b/solutions/3190-find-minimum-operations-to-make-all-elements-divisible-by-three.js
@@ -0,0 +1,21 @@
+/**
+ * 3190. Find Minimum Operations to Make All Elements Divisible by Three
+ * https://leetcode.com/problems/find-minimum-operations-to-make-all-elements-divisible-by-three/
+ * Difficulty: Easy
+ *
+ * You are given an integer array nums. In one operation, you can add or subtract 1 from any
+ * element of nums.
+ *
+ * Return the minimum number of operations to make all elements of nums divisible by 3.
+ */
+
+/**
+ * @param {number[]} nums
+ * @return {number}
+ */
+var minimumOperations = function(nums) {
+  return nums.reduce((operations, num) => {
+    const remainder = num % 3;
+    return operations + Math.min(remainder, 3 - remainder);
+  }, 0);
+};
diff --git a/solutions/3318-find-x-sum-of-all-k-long-subarrays-i.js b/solutions/3318-find-x-sum-of-all-k-long-subarrays-i.js
new file mode 100644
index 00000000..2a030036
--- /dev/null
+++ b/solutions/3318-find-x-sum-of-all-k-long-subarrays-i.js
@@ -0,0 +1,60 @@
+/**
+ * 3318. Find X-Sum of All K-Long Subarrays I
+ * https://leetcode.com/problems/find-x-sum-of-all-k-long-subarrays-i/
+ * Difficulty: Easy
+ *
+ * You are given an array nums of n integers and two integers k and x.
+ *
+ * The x-sum of an array is calculated by the following procedure:
+ * - Count the occurrences of all elements in the array.
+ * - Keep only the occurrences of the top x most frequent elements. If two elements
+ *   have the same number of occurrences, the element with the bigger value is
+ *   considered more frequent.
+ * - Calculate the sum of the resulting array.
+ *
+ * Note that if an array has less than x distinct elements, its x-sum is the sum of the array.
+ *
+ Return an integer array answer of length n - k + 1 where answer[i] is the x-sum of the
+ subarray nums[i..i + k - 1].
+ */
+
+/**
+ * @param {number[]} nums
+ * @param {number} k
+ * @param {number} x
+ * @return {number[]}
+ */
+var findXSum = function(nums, k, x) {
+  const n = nums.length;
+  const result = [];
+
+  for (let i = 0; i <= n - k; i++) {
+    const subarray = nums.slice(i, i + k);
+    result.push(helper(subarray));
+  }
+
+  return result;
+
+  function helper(subarray) {
+    const frequency = new Map();
+
+    for (const num of subarray) {
+      frequency.set(num, (frequency.get(num) || 0) + 1);
+    }
+
+    const elements = Array.from(frequency.entries());
+    elements.sort((a, b) => {
+      if (a[1] !== b[1]) return b[1] - a[1];
+      return b[0] - a[0];
+    });
+
+    const topX = elements.slice(0, x);
+    let sum = 0;
+
+    for (const [value, count] of topX) {
+      sum += value * count;
+    }
+
+    return sum;
+  }
+};
diff --git a/solutions/3512-minimum-operations-to-make-array-sum-divisible-by-k.js b/solutions/3512-minimum-operations-to-make-array-sum-divisible-by-k.js
new file mode 100644
index 00000000..772bb4dc
--- /dev/null
+++ b/solutions/3512-minimum-operations-to-make-array-sum-divisible-by-k.js
@@ -0,0 +1,21 @@
+/**
+ * 3512. Minimum Operations to Make Array Sum Divisible by K
+ * https://leetcode.com/problems/minimum-operations-to-make-array-sum-divisible-by-k/
+ * Difficulty: Easy
+ *
+ * You are given an integer array nums and an integer k. You can perform the following
+ * operation any number of times:
+ * - Select an index i and replace nums[i] with nums[i] - 1.
+ *
+ * Return the minimum number of operations required to make the sum of the array
+ * divisible by k.
+ */
+
+/**
+ * @param {number[]} nums
+ * @param {number} k
+ * @return {number}
+ */
+var minOperations = function(nums, k) {
+  return nums.reduce((sum, n) => sum + n, 0) % k;
+};