|
4 | 4 | * @return {number[]} |
5 | 5 | */ |
6 | 6 | let findAnagrams = function (s, p) { |
| 7 | + let targetMap = makeCountMap(p) |
7 | 8 | let sl = s.length |
8 | 9 | let pl = p.length |
9 | | - let last = sl - pl + 1 |
10 | | - |
| 10 | + // [left,...right] 滑动窗口 |
| 11 | + let left = 0 |
| 12 | + let right = pl - 1 |
| 13 | + let windowMap = makeCountMap(s.substring(left, right + 1)) |
11 | 14 | let res = [] |
12 | | - for (let i = 0; i < last; i++) { |
13 | | - if (isAnagrams(s, p, i)) { |
14 | | - res.push(i) |
| 15 | + |
| 16 | + while (left <= sl - pl && right < sl) { |
| 17 | + if (isAnagrams(windowMap, targetMap)) { |
| 18 | + res.push(left) |
15 | 19 | } |
| 20 | + windowMap[s[left]]-- |
| 21 | + right++ |
| 22 | + left++ |
| 23 | + addCountToMap(windowMap, s[right]) |
16 | 24 | } |
17 | 25 |
|
18 | 26 | return res |
19 | 27 | } |
20 | 28 |
|
21 | | -let isAnagrams = function (s, p, start) { |
22 | | - let pl = p.length |
23 | | - let end = start + pl |
24 | | - |
25 | | - let sub = s.substring(start, end) |
26 | | - let subMap = {} |
27 | | - let pMap = {} |
28 | | - |
29 | | - countStr(sub, subMap) |
30 | | - countStr(p, pMap) |
31 | | - |
32 | | - let subKeys = Object.keys(subMap) |
33 | | - for (let subKey of subKeys) { |
34 | | - if (!pMap[subKey] || subMap[subKey] !== pMap[subKey]) { |
| 29 | +let isAnagrams = function (windowMap, targetMap) { |
| 30 | + let targetKeys = Object.keys(targetMap) |
| 31 | + for (let targetKey of targetKeys) { |
| 32 | + if ( |
| 33 | + !windowMap[targetKey] || |
| 34 | + windowMap[targetKey] !== targetMap[targetKey] |
| 35 | + ) { |
35 | 36 | return false |
36 | 37 | } |
37 | 38 | } |
38 | 39 | return true |
| 40 | +} |
39 | 41 |
|
40 | | - function countStr(str, map) { |
41 | | - for (let i = 0; i < str.length; i++) { |
42 | | - if (!map[str[i]]) { |
43 | | - map[str[i]] = 1 |
44 | | - } else { |
45 | | - map[str[i]]++ |
46 | | - } |
47 | | - } |
| 42 | +function addCountToMap(map, str) { |
| 43 | + if (!map[str]) { |
| 44 | + map[str] = 1 |
| 45 | + } else { |
| 46 | + map[str]++ |
| 47 | + } |
| 48 | +} |
| 49 | + |
| 50 | +function makeCountMap(strs) { |
| 51 | + let map = {} |
| 52 | + for (let i = 0; i < strs.length; i++) { |
| 53 | + let letter = strs[i] |
| 54 | + addCountToMap(map, letter) |
48 | 55 | } |
| 56 | + return map |
49 | 57 | } |
| 58 | + |
| 59 | +console.log(findAnagrams("abab", "ab")) |
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