public class Solution extends Object
828 - Count Unique Characters of All Substrings of a Given String.
Hard
Let’s define a function countUniqueChars(s) that returns the number of unique characters on s.
s = "LEETCODE" then "L", "T", "C", "O", "D" are the unique characters since they appear only once in s, therefore countUniqueChars(s) = 5.Given a string s, return the sum of countUniqueChars(t) where t is a substring of s.
Notice that some substrings can be repeated so in this case you have to count the repeated ones too.
Example 1:
Input: s = “ABC”
Output: 10
Explanation: All possible substrings are: “A”,“B”,“C”,“AB”,“BC” and “ABC”.
Evey substring is composed with only unique letters.
Sum of lengths of all substring is 1 + 1 + 1 + 2 + 2 + 3 = 10
Example 2:
Input: s = “ABA”
Output: 8
Explanation: The same as example 1, except countUniqueChars(“ABA”) = 1.
Example 3:
Input: s = “LEETCODE”
Output: 92
Constraints:
1 <= s.length <= 105s consists of uppercase English letters only.| Constructor and Description |
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Solution() |
public int uniqueLetterString(String s)
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