public class Solution extends Object
2040 - Kth Smallest Product of Two Sorted Arrays.
Hard
Given two sorted 0-indexed integer arrays nums1 and nums2 as well as an integer k, return the kth ( 1-based ) smallest product of nums1[i] * nums2[j] where 0 <= i < nums1.length and 0 <= j < nums2.length.
Example 1:
Input: nums1 = [2,5], nums2 = [3,4], k = 2
Output: 8
Explanation: The 2 smallest products are:
nums1[0] * nums2[0] = 2 * 3 = 6
nums1[0] * nums2[1] = 2 * 4 = 8
The 2nd smallest product is 8.
Example 2:
Input: nums1 = [-4,-2,0,3], nums2 = [2,4], k = 6
Output: 0
Explanation: The 6 smallest products are:
nums1[0] * nums2[1] = (-4) * 4 = -16
nums1[0] * nums2[0] = (-4) * 2 = -8
nums1[1] * nums2[1] = (-2) * 4 = -8
nums1[1] * nums2[0] = (-2) * 2 = -4
nums1[2] * nums2[0] = 0 * 2 = 0
nums1[2] * nums2[1] = 0 * 4 = 0
The 6th smallest product is 0.
Example 3:
Input: nums1 = [-2,-1,0,1,2], nums2 = [-3,-1,2,4,5], k = 3
Output: -6
Explanation: The 3 smallest products are:
nums1[0] * nums2[4] = (-2) * 5 = -10
nums1[0] * nums2[3] = (-2) * 4 = -8
nums1[4] * nums2[0] = 2 * (-3) = -6
The 3rd smallest product is -6.
Constraints:
1 <= nums1.length, nums2.length <= 5 * 104-105 <= nums1[i], nums2[j] <= 1051 <= k <= nums1.length * nums2.lengthnums1 and nums2 are sorted.| Constructor and Description |
|---|
Solution() |
| Modifier and Type | Method and Description |
|---|---|
long |
kthSmallestProduct(int[] nums1,
int[] nums2,
long k) |
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