Class Solution
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- g0101_0200.s0114_flatten_binary_tree_to_linked_list.Solution
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public class Solution extends Object
114 - Flatten Binary Tree to Linked List.Medium
Given the
rootof a binary tree, flatten the tree into a “linked list”:- The “linked list” should use the same
TreeNodeclass where therightchild pointer points to the next node in the list and theleftchild pointer is alwaysnull. - The “linked list” should be in the same order as a pre-order traversal of the binary tree.
Example 1:

Input: root = [1,2,5,3,4,null,6]
Output: [1,null,2,null,3,null,4,null,5,null,6]
Example 2:
Input: root = []
Output: []
Example 3:
Input: root = [0]
Output: [0]
Constraints:
- The number of nodes in the tree is in the range
[0, 2000]. -100 <= Node.val <= 100
Follow up: Can you flatten the tree in-place (with
O(1)extra space)? - The “linked list” should use the same
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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flatten
public void flatten(TreeNode root)
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