Class Solution


  • public class Solution
    extends Object
    318 - Maximum Product of Word Lengths.

    Medium

    Given a string array words, return the maximum value of length(word[i]) * length(word[j]) where the two words do not share common letters. If no such two words exist, return 0.

    Example 1:

    Input: words = [“abcw”,“baz”,“foo”,“bar”,“xtfn”,“abcdef”]

    Output: 16

    Explanation: The two words can be “abcw”, “xtfn”.

    Example 2:

    Input: words = [“a”,“ab”,“abc”,“d”,“cd”,“bcd”,“abcd”]

    Output: 4

    Explanation: The two words can be “ab”, “cd”.

    Example 3:

    Input: words = [“a”,“aa”,“aaa”,“aaaa”]

    Output: 0

    Explanation: No such pair of words.

    Constraints:

    • 2 <= words.length <= 1000
    • 1 <= words[i].length <= 1000
    • words[i] consists only of lowercase English letters.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maxProduct

        public int maxProduct​(String[] words)