Class Solution
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- g0301_0400.s0318_maximum_product_of_word_lengths.Solution
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public class Solution extends Object
318 - Maximum Product of Word Lengths.Medium
Given a string array
words, return the maximum value oflength(word[i]) * length(word[j])where the two words do not share common letters. If no such two words exist, return0.Example 1:
Input: words = [“abcw”,“baz”,“foo”,“bar”,“xtfn”,“abcdef”]
Output: 16
Explanation: The two words can be “abcw”, “xtfn”.
Example 2:
Input: words = [“a”,“ab”,“abc”,“d”,“cd”,“bcd”,“abcd”]
Output: 4
Explanation: The two words can be “ab”, “cd”.
Example 3:
Input: words = [“a”,“aa”,“aaa”,“aaaa”]
Output: 0
Explanation: No such pair of words.
Constraints:
2 <= words.length <= 10001 <= words[i].length <= 1000words[i]consists only of lowercase English letters.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Detail
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maxProduct
public int maxProduct(String[] words)
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