Class Solution
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- g1301_1400.s1334_find_the_city_with_the_smallest_number_of_neighbors_at_a_threshold_distance.Solution
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public class Solution extends Object
1334 - Find the City With the Smallest Number of Neighbors at a Threshold Distance.Medium
There are
ncities numbered from0ton-1. Given the arrayedgeswhereedges[i] = [fromi, toi, weighti]represents a bidirectional and weighted edge between citiesfromiandtoi, and given the integerdistanceThreshold.Return the city with the smallest number of cities that are reachable through some path and whose distance is at most
distanceThreshold, If there are multiple such cities, return the city with the greatest number.Notice that the distance of a path connecting cities i and j is equal to the sum of the edges’ weights along that path.
Example 1:

Input: n = 4, edges = [[0,1,3],[1,2,1],[1,3,4],[2,3,1]], distanceThreshold = 4
Output: 3
Explanation: The figure above describes the graph.
The neighboring cities at a distanceThreshold = 4 for each city are:
City 0 -> [City 1, City 2]
City 1 -> [City 0, City 2, City 3]
City 2 -> [City 0, City 1, City 3]
City 3 -> [City 1, City 2]
Cities 0 and 3 have 2 neighboring cities at a distanceThreshold = 4, but we have to return city 3 since it has the greatest number.
Example 2:

Input: n = 5, edges = [[0,1,2],[0,4,8],[1,2,3],[1,4,2],[2,3,1],[3,4,1]], distanceThreshold = 2
Output: 0
Explanation: The figure above describes the graph.
The neighboring cities at a distanceThreshold = 2 for each city are:
City 0 -> [City 1]
City 1 -> [City 0, City 4]
City 2 -> [City 3, City 4]
City 3 -> [City 2, City 4]
City 4 -> [City 1, City 2, City 3]
The city 0 has 1 neighboring city at a distanceThreshold = 2.
Constraints:
2 <= n <= 1001 <= edges.length <= n * (n - 1) / 2edges[i].length == 30 <= fromi < toi < n1 <= weighti, distanceThreshold <= 10^4- All pairs
(fromi, toi)are distinct.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description intfindTheCity(int n, int[][] edges, int maxDist)
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