Class Solution
- java.lang.Object
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- g1301_1400.s1375_number_of_times_binary_string_is_prefix_aligned.Solution
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public class Solution extends Object
1375 - Number of Times Binary String Is Prefix-Aligned.Medium
You have a 1-indexed binary string of length
nwhere all the bits are0initially. We will flip all the bits of this binary string (i.e., change them from0to1) one by one. You are given a 1-indexed integer arrayflipswhereflips[i]indicates that the bit at indexiwill be flipped in theithstep.A binary string is prefix-aligned if, after the
ithstep, all the bits in the inclusive range[1, i]are ones and all the other bits are zeros.Return the number of times the binary string is prefix-aligned during the flipping process.
Example 1:
Input: flips = [3,2,4,1,5]
Output: 2
Explanation: The binary string is initially “00000”.
After applying step 1: The string becomes “00100”, which is not prefix-aligned.
After applying step 2: The string becomes “01100”, which is not prefix-aligned.
After applying step 3: The string becomes “01110”, which is not prefix-aligned.
After applying step 4: The string becomes “11110”, which is prefix-aligned.
After applying step 5: The string becomes “11111”, which is prefix-aligned.
We can see that the string was prefix-aligned 2 times, so we return 2.
Example 2:
Input: flips = [4,1,2,3]
Output: 1
Explanation: The binary string is initially “0000”.
After applying step 1: The string becomes “0001”, which is not prefix-aligned.
After applying step 2: The string becomes “1001”, which is not prefix-aligned.
After applying step 3: The string becomes “1101”, which is not prefix-aligned.
After applying step 4: The string becomes “1111”, which is prefix-aligned.
We can see that the string was prefix-aligned 1 time, so we return 1.
Constraints:
n == flips.length1 <= n <= 5 * 104flipsis a permutation of the integers in the range[1, n].
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description intnumTimesAllBlue(int[] flips)
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