Class Solution


  • public class Solution
    extends Object
    1888 - Minimum Number of Flips to Make the Binary String Alternating.

    Medium

    You are given a binary string s. You are allowed to perform two types of operations on the string in any sequence:

    • Type-1: Remove the character at the start of the string s and append it to the end of the string.
    • Type-2: Pick any character in s and flip its value, i.e., if its value is '0' it becomes '1' and vice-versa.

    Return the minimum number of type-2 operations you need to perform such that s becomes alternating.

    The string is called alternating if no two adjacent characters are equal.

    • For example, the strings "010" and "1010" are alternating, while the string "0100" is not.

    Example 1:

    Input: s = “111000”

    Output: 2

    Explanation: Use the first operation two times to make s = “100011”.

    Then, use the second operation on the third and sixth elements to make s = “101010”.

    Example 2:

    Input: s = “010”

    Output: 0

    Explanation: The string is already alternating.

    Example 3:

    Input: s = “1110”

    Output: 1

    Explanation: Use the second operation on the second element to make s = “1010”.

    Constraints:

    • 1 <= s.length <= 105
    • s[i] is either '0' or '1'.
    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • minFlips

        public int minFlips​(String s)