Class Solution
- java.lang.Object
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- g1901_2000.s1969_minimum_non_zero_product_of_the_array_elements.Solution
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public class Solution extends Object
1969 - Minimum Non-Zero Product of the Array Elements.Medium
You are given a positive integer
p. Consider an arraynums( 1-indexed ) that consists of the integers in the inclusive range[1, 2p - 1]in their binary representations. You are allowed to do the following operation any number of times:- Choose two elements
xandyfromnums. - Choose a bit in
xand swap it with its corresponding bit iny. Corresponding bit refers to the bit that is in the same position in the other integer.
For example, if
x = 1101andy = 0011, after swapping the2ndbit from the right, we havex = 1111andy = 0001.Find the minimum non-zero product of
numsafter performing the above operation any number of times. Return this product modulo109 + 7.Note: The answer should be the minimum product before the modulo operation is done.
Example 1:
Input: p = 1
Output: 1
Explanation: nums = [1]. There is only one element, so the product equals that element.
Example 2:
Input: p = 2
Output: 6
Explanation: nums = [01, 10, 11].
Any swap would either make the product 0 or stay the same.
Thus, the array product of 1 * 2 * 3 = 6 is already minimized.
Example 3:
Input: p = 3
Output: 1512
Explanation: nums = [001, 010, 011, 100, 101, 110, 111]
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In the first operation we can swap the leftmost bit of the second and fifth elements.
- The resulting array is [001, 110, 011, 100, 001, 110, 111].
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In the second operation we can swap the middle bit of the third and fourth elements.
- The resulting array is [001, 110, 001, 110, 001, 110, 111].
The array product is 1 * 6 * 1 * 6 * 1 * 6 * 7 = 1512, which is the minimum possible product.
Constraints:
1 <= p <= 60
- Choose two elements
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
All Methods Instance Methods Concrete Methods Modifier and Type Method Description intminNonZeroProduct(int p)
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