Class Solution


  • public class Solution
    extends Object
    2529 - Maximum Count of Positive Integer and Negative Integer.

    Easy

    Given an array nums sorted in non-decreasing order, return the maximum between the number of positive integers and the number of negative integers.

    • In other words, if the number of positive integers in nums is pos and the number of negative integers is neg, then return the maximum of pos and neg.

    Note that 0 is neither positive nor negative.

    Example 1:

    Input: nums = [-2,-1,-1,1,2,3]

    Output: 3

    Explanation: There are 3 positive integers and 3 negative integers. The maximum count among them is 3.

    Example 2:

    Input: nums = [-3,-2,-1,0,0,1,2]

    Output: 3

    Explanation: There are 2 positive integers and 3 negative integers. The maximum count among them is 3.

    Example 3:

    Input: nums = [5,20,66,1314]

    Output: 4

    Explanation: There are 4 positive integers and 0 negative integers. The maximum count among them is 4.

    Constraints:

    • 1 <= nums.length <= 2000
    • -2000 <= nums[i] <= 2000
    • nums is sorted in a non-decreasing order.

    Follow up: Can you solve the problem in O(log(n)) time complexity?

    • Constructor Detail

      • Solution

        public Solution()
    • Method Detail

      • maximumCount

        public int maximumCount​(int[] nums)