Class Solution
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- g2601_2700.s2615_sum_of_distances.Solution
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public class Solution extends Object
2615 - Sum of Distances.Medium
You are given a 0-indexed integer array
nums. There exists an arrayarrof lengthnums.length, wherearr[i]is the sum of|i - j|over alljsuch thatnums[j] == nums[i]andj != i. If there is no suchj, setarr[i]to be0.Return the array
arr.Example 1:
Input: nums = [1,3,1,1,2]
Output: [5,0,3,4,0]
Explanation:
When i = 0, nums[0] == nums[2] and nums[0] == nums[3]. Therefore, arr[0] = |0 - 2| + |0 - 3| = 5.
When i = 1, arr[1] = 0 because there is no other index with value 3.
When i = 2, nums[2] == nums[0] and nums[2] == nums[3]. Therefore, arr[2] = |2 - 0| + |2 - 3| = 3.
When i = 3, nums[3] == nums[0] and nums[3] == nums[2]. Therefore, arr[3] = |3 - 0| + |3 - 2| = 4.
When i = 4, arr[4] = 0 because there is no other index with value 2.
Example 2:
Input: nums = [0,5,3]
Output: [0,0,0]
Explanation: Since each element in nums is distinct, arr[i] = 0 for all i.
Constraints:
1 <= nums.length <= 1050 <= nums[i] <= 109
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Constructor Summary
Constructors Constructor Description Solution()
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