Class Solution
java.lang.Object
g1301_1400.s1309_decrypt_string_from_alphabet_to_integer_mapping.Solution
1309 - Decrypt String from Alphabet to Integer Mapping.
Easy
You are given a string s formed by digits and '#'. We want to map s to English lowercase characters as follows:
- Characters (
'a'to'i')are represented by ('1'to'9') respectively. - Characters (
'j'to'z')are represented by ('10#'to'26#') respectively.
Return the string formed after mapping.
The test cases are generated so that a unique mapping will always exist.
Example 1:
Input: s = “10#11#12”
Output: “jkab”
Explanation: “j” -> “10#” , “k” -> “11#” , “a” -> “1” , “b” -> “2”.
Example 2:
Input: s = “1326#”
Output: “acz”
Constraints:
1 <= s.length <= 1000sconsists of digits and the'#'letter.swill be a valid string such that mapping is always possible.
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Solution
public Solution()
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freqAlphabets
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