Package g2401_2500.s2442_count_number_of_distinct_integers_after_reverse_operations

Class Solution

java.lang.Object
g2401_2500.s2442_count_number_of_distinct_integers_after_reverse_operations.Solution
public class Solution extends Object
2442 - Count Number of Distinct Integers After Reverse Operations.

Medium

You are given an array nums consisting of positive integers.

You have to take each integer in the array, reverse its digits , and add it to the end of the array. You should apply this operation to the original integers in nums.

Return the number of distinct integers in the final array.

Example 1:

Input: nums = [1,13,10,12,31]

Output: 6

Explanation: After including the reverse of each number, the resulting array is [1,13,10,12,31,1,31,1,21,13]. The reversed integers that were added to the end of the array are underlined. Note that for the integer 10, after reversing it, it becomes 01 which is just 1. The number of distinct integers in this array is 6 (The numbers 1, 10, 12, 13, 21, and 31).

Example 2:

Input: nums = [2,2,2]

Output: 1

Explanation: After including the reverse of each number, the resulting array is [2,2,2,2,2,2]. The number of distinct integers in this array is 1 (The number 2).

Constraints:

  • 1 <= nums.length <= 105
  • 1 <= nums[i] <= 106

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • countDistinctIntegers

      public int countDistinctIntegers(int[] nums)