Class Solution
java.lang.Object
g3101_3200.s3194_minimum_average_of_smallest_and_largest_elements.Solution
3194 - Minimum Average of Smallest and Largest Elements.
Easy
You have an array of floating point numbers averages which is initially empty. You are given an array nums of n integers where n is even.
You repeat the following procedure n / 2 times:
- Remove the smallest element,
minElement, and the largest elementmaxElement, fromnums. - Add
(minElement + maxElement) / 2toaverages.
Return the minimum element in averages.
Example 1:
Input: nums = [7,8,3,4,15,13,4,1]
Output: 5.5
Explanation:
| Step | nums | averages |
|---|---|---|
| 0 | [7,8,3,4,15,13,4,1] | [] |
| 1 | [7,8,3,4,13,4] | [8] |
| 2 | [7,8,4,4] | [8, 8] |
| 3 | [7,4] | [8, 8, 6] |
| 4 | [] | [8, 8, 6, 5.5] |
The smallest element of averages, 5.5, is returned.
Example 2:
Input: nums = [1,9,8,3,10,5]
Output: 5.5
Explanation:
| Step | nums | averages |
|---|---|---|
| 0 | [1,9,8,3,10,5] | [] |
| 1 | [9,8,3,5] | [5.5] |
| 2 | [8,5] | [5.5, 6] |
| 3 | [] | [5.5, 6, 6.5] |
Example 3:
Input: nums = [1,2,3,7,8,9]
Output: 5.0
Explanation:
| Step | nums | averages |
|---|---|---|
| 0 | [1,2,3,7,8,9] | [] |
| 1 | [2,3,7,8] | [5] |
| 2 | [3,7] | [5, 5] |
| 3 | [] | [5, 5, 5] |
Constraints:
2 <= n == nums.length <= 50nis even.1 <= nums[i] <= 50
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Constructor Summary
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Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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minimumAverage
public double minimumAverage(int[] nums)
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