Package g1101_1200.s1190_reverse_substrings_between_each_pair_of_parentheses

Class Solution

java.lang.Object
g1101_1200.s1190_reverse_substrings_between_each_pair_of_parentheses.Solution
public class Solution extends Object
1190 - Reverse Substrings Between Each Pair of Parentheses.

Medium

You are given a string s that consists of lower case English letters and brackets.

Reverse the strings in each pair of matching parentheses, starting from the innermost one.

Your result should not contain any brackets.

Example 1:

Input: s = “(abcd)”

Output: “dcba”

Example 2:

Input: s = “(u(love)i)”

Output: “iloveu”

Explanation: The substring “love” is reversed first, then the whole string is reversed.

Example 3:

Input: s = “(ed(et(oc))el)”

Output: “leetcode”

Explanation: First, we reverse the substring “oc”, then “etco”, and finally, the whole string.

Constraints:

  • 1 <= s.length <= 2000
  • s only contains lower case English characters and parentheses.
  • It is guaranteed that all parentheses are balanced.

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • reverseParentheses

      public String reverseParentheses(String s)