Package g0001_0100.s0030_substring_with_concatenation_of_all_words

Class Solution

java.lang.Object

g0001_0100.s0030_substring_with_concatenation_of_all_words.Solution

public class Solution
extends Object

30 - Substring with Concatenation of All Words\. Hard You are given a string `s` and an array of strings `words` of **the same length**. Return all starting indices of substring(s) in `s` that is a concatenation of each word in `words` **exactly once** , **in any order** , and **without any intervening characters**. You can return the answer in **any order**. **Example 1:** **Input:** s = "barfoothefoobarman", words = ["foo","bar"] **Output:** [0,9] **Explanation:** Substrings starting at index 0 and 9 are "barfoo" and "foobar" respectively. The output order does not matter, returning [9,0] is fine too. **Example 2:** **Input:** s = "wordgoodgoodgoodbestword", words = ["word","good","best","word"] **Output:** [] **Example 3:** **Input:** s = "barfoofoobarthefoobarman", words = ["bar","foo","the"] **Output:** [6,9,12] **Constraints:** * 1 <= s.length <= 104 * `s` consists of lower-case English letters. * `1 <= words.length <= 5000` * `1 <= words[i].length <= 30` * `words[i]` consists of lower-case English letters.

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
List<Integer>	findSubstring(String s, String[] words)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details

Solution

public Solution()

Method Details

findSubstring

public List<Integer> findSubstring(String s,
 String[] words)