Package g0101_0200.s0153_find_minimum_in_rotated_sorted_array

Class Solution

java.lang.Object
g0101_0200.s0153_find_minimum_in_rotated_sorted_array.Solution
public class Solution extends Object
153 - Find Minimum in Rotated Sorted Array\. Medium Suppose an array of length `n` sorted in ascending order is **rotated** between `1` and `n` times. For example, the array `nums = [0,1,2,4,5,6,7]` might become: * `[4,5,6,7,0,1,2]` if it was rotated `4` times. * `[0,1,2,4,5,6,7]` if it was rotated `7` times. Notice that **rotating** an array `[a[0], a[1], a[2], ..., a[n-1]]` 1 time results in the array `[a[n-1], a[0], a[1], a[2], ..., a[n-2]]`. Given the sorted rotated array `nums` of **unique** elements, return _the minimum element of this array_. You must write an algorithm that runs in `O(log n) time.` **Example 1:** **Input:** nums = [3,4,5,1,2] **Output:** 1 **Explanation:** The original array was [1,2,3,4,5] rotated 3 times. **Example 2:** **Input:** nums = [4,5,6,7,0,1,2] **Output:** 0 **Explanation:** The original array was [0,1,2,4,5,6,7] and it was rotated 4 times. **Example 3:** **Input:** nums = [11,13,15,17] **Output:** 11 **Explanation:** The original array was [11,13,15,17] and it was rotated 4 times. **Constraints:** * `n == nums.length` * `1 <= n <= 5000` * `-5000 <= nums[i] <= 5000` * All the integers of `nums` are **unique**. * `nums` is sorted and rotated between `1` and `n` times.

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • findMin

      public int findMin(int[] nums)