Package g0401_0500.s0451_sort_characters_by_frequency

Class Solution

java.lang.Object

g0401_0500.s0451_sort_characters_by_frequency.Solution

public class Solution
extends Object

451 - Sort Characters By Frequency\. Medium Given a string `s`, sort it in **decreasing order** based on the **frequency** of the characters. The **frequency** of a character is the number of times it appears in the string. Return _the sorted string_. If there are multiple answers, return _any of them_. **Example 1:** **Input:** s = "tree" **Output:** "eert" **Explanation:** 'e' appears twice while 'r' and 't' both appear once. So 'e' must appear before both 'r' and 't'. Therefore "eetr" is also a valid answer. **Example 2:** **Input:** s = "cccaaa" **Output:** "aaaccc" **Explanation:** Both 'c' and 'a' appear three times, so both "cccaaa" and "aaaccc" are valid answers. Note that "cacaca" is incorrect, as the same characters must be together. **Example 3:** **Input:** s = "Aabb" **Output:** "bbAa" **Explanation:** "bbaA" is also a valid answer, but "Aabb" is incorrect. Note that 'A' and 'a' are treated as two different characters. **Constraints:** * 1 <= s.length <= 5 * 105 * `s` consists of uppercase and lowercase English letters and digits.

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
String	frequencySort(String s)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details

Solution

public Solution()

Method Details

frequencySort

public String frequencySort(String s)