java.lang.Object
g0601_0700.s0689_maximum_sum_of_3_non_overlapping_subarrays.Solution

public class Solution extends Object
689 - Maximum Sum of 3 Non-Overlapping Subarrays\. Hard Given an integer array `nums` and an integer `k`, find three non-overlapping subarrays of length `k` with maximum sum and return them. Return the result as a list of indices representing the starting position of each interval ( **0-indexed** ). If there are multiple answers, return the lexicographically smallest one. **Example 1:** **Input:** nums = [1,2,1,2,6,7,5,1], k = 2 **Output:** [0,3,5] **Explanation:** Subarrays [1, 2], [2, 6], [7, 5] correspond to the starting indices [0, 3, 5]. We could have also taken [2, 1], but an answer of [1, 3, 5] would be lexicographically larger. **Example 2:** **Input:** nums = [1,2,1,2,1,2,1,2,1], k = 2 **Output:** [0,2,4] **Constraints:** * 1 <= nums.length <= 2 * 104 * 1 <= nums[i] < 216 * `1 <= k <= floor(nums.length / 3)`
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • maxSumOfThreeSubarrays

      public int[] maxSumOfThreeSubarrays(int[] nums, int k)