java.lang.Object
g1001_1100.s1008_construct_binary_search_tree_from_preorder_traversal.Solution

public class Solution extends Object
1008 - Construct Binary Search Tree from Preorder Traversal\. Medium Given an array of integers preorder, which represents the **preorder traversal** of a BST (i.e., **binary search tree** ), construct the tree and return _its root_. It is **guaranteed** that there is always possible to find a binary search tree with the given requirements for the given test cases. A **binary search tree** is a binary tree where for every node, any descendant of `Node.left` has a value **strictly less than** `Node.val`, and any descendant of `Node.right` has a value **strictly greater than** `Node.val`. A **preorder traversal** of a binary tree displays the value of the node first, then traverses `Node.left`, then traverses `Node.right`. **Example 1:** ![](https://assets.leetcode.com/uploads/2019/03/06/1266.png) **Input:** preorder = [8,5,1,7,10,12] **Output:** [8,5,10,1,7,null,12] **Example 2:** **Input:** preorder = [1,3] **Output:** [1,null,3] **Constraints:** * `1 <= preorder.length <= 100` * `1 <= preorder[i] <= 1000` * All the values of `preorder` are **unique**.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • bstFromPreorder

      public TreeNode bstFromPreorder(int[] preorder)