Class Solution
java.lang.Object
g1201_1300.s1269_number_of_ways_to_stay_in_the_same_place_after_some_steps.Solution
1269 - Number of Ways to Stay in the Same Place After Some Steps\.
Hard
You have a pointer at index `0` in an array of size `arrLen`. At each step, you can move 1 position to the left, 1 position to the right in the array, or stay in the same place (The pointer should not be placed outside the array at any time).
Given two integers `steps` and `arrLen`, return the number of ways such that your pointer still at index `0` after **exactly** `steps` steps. Since the answer may be too large, return it **modulo**
109 + 7.
**Example 1:**
**Input:** steps = 3, arrLen = 2
**Output:** 4
**Explanation:** There are 4 differents ways to stay at index 0 after 3 steps.
Right, Left, Stay
Stay, Right, Left
Right, Stay, Left
Stay, Stay, Stay
**Example 2:**
**Input:** steps = 2, arrLen = 4
**Output:** 2
**Explanation:** There are 2 differents ways to stay at index 0 after 2 steps
Right, Left
Stay, Stay
**Example 3:**
**Input:** steps = 4, arrLen = 2
**Output:** 8
**Constraints:**
* `1 <= steps <= 500`
* 1 <= arrLen <= 106-
Constructor Summary
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Method Summary
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Constructor Details
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Solution
public Solution()
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Method Details
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numWays
public int numWays(int steps, int arrLen)
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