java.lang.Object
g1301_1400.s1334_find_the_city_with_the_smallest_number_of_neighbors_at_a_threshold_distance.Solution

public class Solution extends Object
1334 - Find the City With the Smallest Number of Neighbors at a Threshold Distance\. Medium There are `n` cities numbered from `0` to `n-1`. Given the array `edges` where edges[i] = [fromi, toi, weighti] represents a bidirectional and weighted edge between cities fromi and toi, and given the integer `distanceThreshold`. Return the city with the smallest number of cities that are reachable through some path and whose distance is **at most** `distanceThreshold`, If there are multiple such cities, return the city with the greatest number. Notice that the distance of a path connecting cities _**i**_ and _**j**_ is equal to the sum of the edges' weights along that path. **Example 1:** ![](https://assets.leetcode.com/uploads/2020/01/16/find_the_city_01.png) **Input:** n = 4, edges = \[\[0,1,3],[1,2,1],[1,3,4],[2,3,1]], distanceThreshold = 4 **Output:** 3 **Explanation:** The figure above describes the graph. The neighboring cities at a distanceThreshold = 4 for each city are: City 0 -> [City 1, City 2] City 1 -> [City 0, City 2, City 3] City 2 -> [City 0, City 1, City 3] City 3 -> [City 1, City 2] Cities 0 and 3 have 2 neighboring cities at a distanceThreshold = 4, but we have to return city 3 since it has the greatest number. **Example 2:** ![](https://assets.leetcode.com/uploads/2020/01/16/find_the_city_02.png) **Input:** n = 5, edges = \[\[0,1,2],[0,4,8],[1,2,3],[1,4,2],[2,3,1],[3,4,1]], distanceThreshold = 2 **Output:** 0 **Explanation:** The figure above describes the graph. The neighboring cities at a distanceThreshold = 2 for each city are: City 0 -> [City 1] City 1 -> [City 0, City 4] City 2 -> [City 3, City 4] City 3 -> [City 2, City 4] City 4 -> [City 1, City 2, City 3] The city 0 has 1 neighboring city at a distanceThreshold = 2. **Constraints:** * `2 <= n <= 100` * `1 <= edges.length <= n * (n - 1) / 2` * `edges[i].length == 3` * 0 <= fromi < toi < n * 1 <= weighti, distanceThreshold <= 10^4 * All pairs (fromi, toi) are distinct.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • findTheCity

      public int findTheCity(int n, int[][] edges, int maxDist)