Class Solution
java.lang.Object
g1301_1400.s1337_the_k_weakest_rows_in_a_matrix.Solution
1337 - The K Weakest Rows in a Matrix\.
Easy
You are given an `m x n` binary matrix `mat` of `1`'s (representing soldiers) and `0`'s (representing civilians). The soldiers are positioned **in front** of the civilians. That is, all the `1`'s will appear to the **left** of all the `0`'s in each row.
A row `i` is **weaker** than a row `j` if one of the following is true:
* The number of soldiers in row `i` is less than the number of soldiers in row `j`.
* Both rows have the same number of soldiers and `i < j`.
Return _the indices of the_ `k` _**weakest** rows in the matrix ordered from weakest to strongest_.
**Example 1:**
**Input:** mat =
[[1,1,0,0,0],
[1,1,1,1,0],
[1,0,0,0,0],
[1,1,0,0,0],
[1,1,1,1,1]], k = 3
**Output:** [2,0,3]
**Explanation:** The number of soldiers in each row is:
- Row 0: 2
- Row 1: 4
- Row 2: 1
- Row 3: 2
- Row 4: 5
The rows ordered from weakest to strongest are [2,0,3,1,4].
**Example 2:**
**Input:** mat = \[\[1,0,0,0], [1,1,1,1], [1,0,0,0], [1,0,0,0]], k = 2
**Output:** [0,2]
**Explanation:** The number of soldiers in each row is:
- Row 0: 1
- Row 1: 4
- Row 2: 1
- Row 3: 1
The rows ordered from weakest to strongest are [0,2,3,1].
**Constraints:**
* `m == mat.length`
* `n == mat[i].length`
* `2 <= n, m <= 100`
* `1 <= k <= m`
* `matrix[i][j]` is either 0 or 1.
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Solution
public Solution()
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kWeakestRows
public int[] kWeakestRows(int[][] mat, int k)
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