java.lang.Object
g1301_1400.s1337_the_k_weakest_rows_in_a_matrix.Solution

public class Solution extends Object
1337 - The K Weakest Rows in a Matrix\. Easy You are given an `m x n` binary matrix `mat` of `1`'s (representing soldiers) and `0`'s (representing civilians). The soldiers are positioned **in front** of the civilians. That is, all the `1`'s will appear to the **left** of all the `0`'s in each row. A row `i` is **weaker** than a row `j` if one of the following is true: * The number of soldiers in row `i` is less than the number of soldiers in row `j`. * Both rows have the same number of soldiers and `i < j`. Return _the indices of the_ `k` _**weakest** rows in the matrix ordered from weakest to strongest_. **Example 1:** **Input:** mat = [[1,1,0,0,0], [1,1,1,1,0], [1,0,0,0,0], [1,1,0,0,0], [1,1,1,1,1]], k = 3 **Output:** [2,0,3] **Explanation:** The number of soldiers in each row is: - Row 0: 2 - Row 1: 4 - Row 2: 1 - Row 3: 2 - Row 4: 5 The rows ordered from weakest to strongest are [2,0,3,1,4]. **Example 2:** **Input:** mat = \[\[1,0,0,0], [1,1,1,1], [1,0,0,0], [1,0,0,0]], k = 2 **Output:** [0,2] **Explanation:** The number of soldiers in each row is: - Row 0: 1 - Row 1: 4 - Row 2: 1 - Row 3: 1 The rows ordered from weakest to strongest are [0,2,3,1]. **Constraints:** * `m == mat.length` * `n == mat[i].length` * `2 <= n, m <= 100` * `1 <= k <= m` * `matrix[i][j]` is either 0 or 1.
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • kWeakestRows

      public int[] kWeakestRows(int[][] mat, int k)