java.lang.Object
g1301_1400.s1356_sort_integers_by_the_number_of_1_bits.Solution

public class Solution extends Object
1356 - Sort Integers by The Number of 1 Bits\. Easy You are given an integer array `arr`. Sort the integers in the array in ascending order by the number of `1`'s in their binary representation and in case of two or more integers have the same number of `1`'s you have to sort them in ascending order. Return _the array after sorting it_. **Example 1:** **Input:** arr = [0,1,2,3,4,5,6,7,8] **Output:** [0,1,2,4,8,3,5,6,7] **Explantion:** [0] is the only integer with 0 bits. [1,2,4,8] all have 1 bit. [3,5,6] have 2 bits. [7] has 3 bits. The sorted array by bits is [0,1,2,4,8,3,5,6,7] **Example 2:** **Input:** arr = [1024,512,256,128,64,32,16,8,4,2,1] **Output:** [1,2,4,8,16,32,64,128,256,512,1024] **Explantion:** All integers have 1 bit in the binary representation, you should just sort them in ascending order. **Constraints:** * `1 <= arr.length <= 500` * 0 <= arr[i] <= 104
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • sortByBits

      public int[] sortByBits(int[] arr)