Class Solution
java.lang.Object
g1301_1400.s1368_minimum_cost_to_make_at_least_one_valid_path_in_a_grid.Solution
1368 - Minimum Cost to Make at Least One Valid Path in a Grid\.
Hard
Given an `m x n` grid. Each cell of the grid has a sign pointing to the next cell you should visit if you are currently in this cell. The sign of `grid[i][j]` can be:
* `1` which means go to the cell to the right. (i.e go from `grid[i][j]` to `grid[i][j + 1]`)
* `2` which means go to the cell to the left. (i.e go from `grid[i][j]` to `grid[i][j - 1]`)
* `3` which means go to the lower cell. (i.e go from `grid[i][j]` to `grid[i + 1][j]`)
* `4` which means go to the upper cell. (i.e go from `grid[i][j]` to `grid[i - 1][j]`)
Notice that there could be some signs on the cells of the grid that point outside the grid.
You will initially start at the upper left cell `(0, 0)`. A valid path in the grid is a path that starts from the upper left cell `(0, 0)` and ends at the bottom-right cell `(m - 1, n - 1)` following the signs on the grid. The valid path does not have to be the shortest.
You can modify the sign on a cell with `cost = 1`. You can modify the sign on a cell **one time only**.
Return _the minimum cost to make the grid have at least one valid path_.
**Example 1:**

**Input:** grid = \[\[1,1,1,1],[2,2,2,2],[1,1,1,1],[2,2,2,2]]
**Output:** 3
**Explanation:** You will start at point (0, 0). The path to (3, 3) is as follows. (0, 0) --> (0, 1) --> (0, 2) --> (0, 3) change the arrow to down with cost = 1 --> (1, 3) --> (1, 2) --> (1, 1) --> (1, 0) change the arrow to down with cost = 1 --> (2, 0) --> (2, 1) --> (2, 2) --> (2, 3) change the arrow to down with cost = 1 --> (3, 3) The total cost = 3.
**Example 2:**

**Input:** grid = \[\[1,1,3],[3,2,2],[1,1,4]]
**Output:** 0
**Explanation:** You can follow the path from (0, 0) to (2, 2).
**Example 3:**

**Input:** grid = \[\[1,2],[4,3]]
**Output:** 1
**Constraints:**
* `m == grid.length`
* `n == grid[i].length`
* `1 <= m, n <= 100`
* `1 <= grid[i][j] <= 4`
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Constructor Summary
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Solution
public Solution()
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Method Details
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minCost
public int minCost(int[][] grid)
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