Class Solution
java.lang.Object
g1401_1500.s1449_form_largest_integer_with_digits_that_add_up_to_target.Solution
1449 - Form Largest Integer With Digits That Add up to Target\.
Hard
Given an array of integers `cost` and an integer `target`, return _the **maximum** integer you can paint under the following rules_:
* The cost of painting a digit `(i + 1)` is given by `cost[i]` ( **0-indexed** ).
* The total cost used must be equal to `target`.
* The integer does not have `0` digits.
Since the answer may be very large, return it as a string. If there is no way to paint any integer given the condition, return `"0"`.
**Example 1:**
**Input:** cost = [4,3,2,5,6,7,2,5,5], target = 9
**Output:** "7772"
**Explanation:** The cost to paint the digit '7' is 2, and the digit '2' is 3. Then cost("7772") = 2\*3+ 3\*1 = 9. You could also paint "977", but "7772" is the largest number.
**Digit cost**
1 -> 4
2 -> 3
3 -> 2
4 -> 5
5 -> 6
6 -> 7
7 -> 2
8 -> 5
9 -> 5
**Example 2:**
**Input:** cost = [7,6,5,5,5,6,8,7,8], target = 12
**Output:** "85"
**Explanation:** The cost to paint the digit '8' is 7, and the digit '5' is 5. Then cost("85") = 7 + 5 = 12.
**Example 3:**
**Input:** cost = [2,4,6,2,4,6,4,4,4], target = 5
**Output:** "0"
**Explanation:** It is impossible to paint any integer with total cost equal to target.
**Constraints:**
* `cost.length == 9`
* `1 <= cost[i], target <= 5000`
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Solution
public Solution()
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largestNumber
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