Package g1801_1900.s1802_maximum_value_at_a_given_index_in_a_bounded_array

Class Solution

java.lang.Object

g1801_1900.s1802_maximum_value_at_a_given_index_in_a_bounded_array.Solution

public class Solution
extends Object

1802 - Maximum Value at a Given Index in a Bounded Array\. Medium You are given three positive integers: `n`, `index`, and `maxSum`. You want to construct an array `nums` ( **0-indexed** ) that satisfies the following conditions: * `nums.length == n` * `nums[i]` is a **positive** integer where `0 <= i < n`. * `abs(nums[i] - nums[i+1]) <= 1` where `0 <= i < n-1`. * The sum of all the elements of `nums` does not exceed `maxSum`. * `nums[index]` is **maximized**. Return `nums[index]` _of the constructed array_. Note that `abs(x)` equals `x` if `x >= 0`, and `-x` otherwise. **Example 1:** **Input:** n = 4, index = 2, maxSum = 6 **Output:** 2 **Explanation:** nums = [1,2, **2** ,1] is one array that satisfies all the conditions. There are no arrays that satisfy all the conditions and have nums[2] == 3, so 2 is the maximum nums[2]. **Example 2:** **Input:** n = 6, index = 1, maxSum = 10 **Output:** 3 **Constraints:** * 1 <= n <= maxSum <= 109 * `0 <= index < n`

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
int	maxValue(int n, int index, int maxSum)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details

Solution

public Solution()

Method Details

maxValue

public int maxValue(int n,
 int index,
 int maxSum)