java.lang.Object
g1801_1900.s1803_count_pairs_with_xor_in_a_range.Solution

public class Solution extends Object
1803 - Count Pairs With XOR in a Range\. Hard Given a **(0-indexed)** integer array `nums` and two integers `low` and `high`, return _the number of **nice pairs**_. A **nice pair** is a pair `(i, j)` where `0 <= i < j < nums.length` and `low <= (nums[i] XOR nums[j]) <= high`. **Example 1:** **Input:** nums = [1,4,2,7], low = 2, high = 6 **Output:** 6 **Explanation:** All nice pairs (i, j) are as follows: - (0, 1): nums[0] XOR nums[1] = 5 - (0, 2): nums[0] XOR nums[2] = 3 - (0, 3): nums[0] XOR nums[3] = 6 - (1, 2): nums[1] XOR nums[2] = 6 - (1, 3): nums[1] XOR nums[3] = 3 - (2, 3): nums[2] XOR nums[3] = 5 **Example 2:** **Input:** nums = [9,8,4,2,1], low = 5, high = 14 **Output:** 8 **Explanation:** All nice pairs (i, j) are as follows: - (0, 2): nums[0] XOR nums[2] = 13 - (0, 3): nums[0] XOR nums[3] = 11 - (0, 4): nums[0] XOR nums[4] = 8 - (1, 2): nums[1] XOR nums[2] = 12 - (1, 3): nums[1] XOR nums[3] = 10 - (1, 4): nums[1] XOR nums[4] = 9 - (2, 3): nums[2] XOR nums[3] = 6 - (2, 4): nums[2] XOR nums[4] = 5 **Constraints:** * 1 <= nums.length <= 2 * 104 * 1 <= nums[i] <= 2 * 104 * 1 <= low <= high <= 2 * 104
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • countPairs

      public int countPairs(int[] nums, int low, int high)