Package g1801_1900.s1839_longest_substring_of_all_vowels_in_order

Class Solution

java.lang.Object

g1801_1900.s1839_longest_substring_of_all_vowels_in_order.Solution

public class Solution
extends Object

1839 - Longest Substring Of All Vowels in Order\. Medium A string is considered **beautiful** if it satisfies the following conditions: * Each of the 5 English vowels (`'a'`, `'e'`, `'i'`, `'o'`, `'u'`) must appear **at least once** in it. * The letters must be sorted in **alphabetical order** (i.e. all `'a'`s before `'e'`s, all `'e'`s before `'i'`s, etc.). For example, strings `"aeiou"` and `"aaaaaaeiiiioou"` are considered **beautiful** , but `"uaeio"`, `"aeoiu"`, and `"aaaeeeooo"` are **not beautiful**. Given a string `word` consisting of English vowels, return _the **length of the longest beautiful substring** of_ `word`_. If no such substring exists, return_ `0`. A **substring** is a contiguous sequence of characters in a string. **Example 1:** **Input:** word = "aeiaaioaaaaeiiiiouuuooaauuaeiu" **Output:** 13 **Explanation:** The longest beautiful substring in word is "aaaaeiiiiouuu" of length 13. **Example 2:** **Input:** word = "aeeeiiiioooauuuaeiou" **Output:** 5 **Explanation:** The longest beautiful substring in word is "aeiou" of length 5. **Example 3:** **Input:** word = "a" **Output:** 0 **Explanation:** There is no beautiful substring, so return 0. **Constraints:** * 1 <= word.length <= 5 * 105 * `word` consists of characters `'a'`, `'e'`, `'i'`, `'o'`, and `'u'`.

Constructor Summary

Constructors

Constructor	Description
Solution()

Method Summary

Modifier and Type	Method	Description
int	longestBeautifulSubstring(String word)

Methods inherited from class java.lang.Object

clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait

Constructor Details

Solution

public Solution()

Method Details

longestBeautifulSubstring

public int longestBeautifulSubstring(String word)