Class Solution
java.lang.Object
g1801_1900.s1888_minimum_number_of_flips_to_make_the_binary_string_alternating.Solution
1888 - Minimum Number of Flips to Make the Binary String Alternating\.
Medium
You are given a binary string `s`. You are allowed to perform two types of operations on the string in any sequence:
* **Type-1: Remove** the character at the start of the string `s` and **append** it to the end of the string.
* **Type-2: Pick** any character in `s` and **flip** its value, i.e., if its value is `'0'` it becomes `'1'` and vice-versa.
Return _the **minimum** number of **type-2** operations you need to perform_ _such that_ `s` _becomes **alternating**._
The string is called **alternating** if no two adjacent characters are equal.
* For example, the strings `"010"` and `"1010"` are alternating, while the string `"0100"` is not.
**Example 1:**
**Input:** s = "111000"
**Output:** 2
**Explanation:** Use the first operation two times to make s = "100011".
Then, use the second operation on the third and sixth elements to make s = "101010".
**Example 2:**
**Input:** s = "010"
**Output:** 0
**Explanation:** The string is already alternating.
**Example 3:**
**Input:** s = "1110"
**Output:** 1
**Explanation:** Use the second operation on the second element to make s = "1010".
**Constraints:**
*
1 <= s.length <= 105
* `s[i]` is either `'0'` or `'1'`.-
Constructor Summary
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Solution
public Solution()
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minFlips
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