java.lang.Object
g1901_2000.s1968_array_with_elements_not_equal_to_average_of_neighbors.Solution

public class Solution extends Object
1968 - Array With Elements Not Equal to Average of Neighbors\. Medium You are given a **0-indexed** array `nums` of **distinct** integers. You want to rearrange the elements in the array such that every element in the rearranged array is **not** equal to the **average** of its neighbors. More formally, the rearranged array should have the property such that for every `i` in the range `1 <= i < nums.length - 1`, `(nums[i-1] + nums[i+1]) / 2` is **not** equal to `nums[i]`. Return _**any** rearrangement of_ `nums` _that meets the requirements_. **Example 1:** **Input:** nums = [1,2,3,4,5] **Output:** [1,2,4,5,3] **Explanation:** When i=1, nums[i] = 2, and the average of its neighbors is (1+4) / 2 = 2.5. When i=2, nums[i] = 4, and the average of its neighbors is (2+5) / 2 = 3.5. When i=3, nums[i] = 5, and the average of its neighbors is (4+3) / 2 = 3.5. **Example 2:** **Input:** nums = [6,2,0,9,7] **Output:** [9,7,6,2,0] **Explanation:** When i=1, nums[i] = 7, and the average of its neighbors is (9+6) / 2 = 7.5. When i=2, nums[i] = 6, and the average of its neighbors is (7+2) / 2 = 4.5. When i=3, nums[i] = 2, and the average of its neighbors is (6+0) / 2 = 3. **Constraints:** * 3 <= nums.length <= 105 * 0 <= nums[i] <= 105
  • Constructor Details

    • Solution

      public Solution()
  • Method Details

    • rearrangeArray

      public int[] rearrangeArray(int[] nums)