Class Solution
java.lang.Object
g2101_2200.s2120_execution_of_all_suffix_instructions_staying_in_a_grid.Solution
2120 - Execution of All Suffix Instructions Staying in a Grid\.
Medium
There is an `n x n` grid, with the top-left cell at `(0, 0)` and the bottom-right cell at `(n - 1, n - 1)`. You are given the integer `n` and an integer array `startPos` where
startPos = [startrow, startcol] indicates that a robot is initially at cell (startrow, startcol).
You are also given a **0-indexed** string `s` of length `m` where `s[i]` is the ith instruction for the robot: `'L'` (move left), `'R'` (move right), `'U'` (move up), and `'D'` (move down).
The robot can begin executing from any ith instruction in `s`. It executes the instructions one by one towards the end of `s` but it stops if either of these conditions is met:
* The next instruction will move the robot off the grid.
* There are no more instructions left to execute.
Return _an array_ `answer` _of length_ `m` _where_ `answer[i]` _is **the number of instructions** the robot can execute if the robot **begins executing from** the_ ith _instruction in_ `s`.
**Example 1:**

**Input:** n = 3, startPos = [0,1], s = "RRDDLU"
**Output:** [1,5,4,3,1,0]
**Explanation:** Starting from startPos and beginning execution from the ith instruction:
- 0th: "**R**RDDLU". Only one instruction "R" can be executed before it moves off the grid.
- 1st: "**RDDLU**". All five instructions can be executed while it stays in the grid and ends at (1, 1).
- 2nd: "**DDLU**". All four instructions can be executed while it stays in the grid and ends at (1, 0).
- 3rd: "**DLU**". All three instructions can be executed while it stays in the grid and ends at (0, 0).
- 4th: "**L**U". Only one instruction "L" can be executed before it moves off the grid.
- 5th: "U". If moving up, it would move off the grid.
**Example 2:**

**Input:** n = 2, startPos = [1,1], s = "LURD"
**Output:** [4,1,0,0]
**Explanation:**
- 0th: "**LURD**".
- 1st: "**U**RD".
- 2nd: "RD".
- 3rd: "D".
**Example 3:**

**Input:** n = 1, startPos = [0,0], s = "LRUD"
**Output:** [0,0,0,0]
**Explanation:** No matter which instruction the robot begins execution from, it would move off the grid.
**Constraints:**
* `m == s.length`
* `1 <= n, m <= 500`
* `startPos.length == 2`
* 0 <= startrow, startcol < n
* `s` consists of `'L'`, `'R'`, `'U'`, and `'D'`.-
Constructor Summary
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Solution
public Solution()
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Method Details
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executeInstructions
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