Package g2101_2200.s2124_check_if_all_as_appears_before_all_bs

Class Solution

java.lang.Object
g2101_2200.s2124_check_if_all_as_appears_before_all_bs.Solution
public class Solution extends Object
2124 - Check if All A's Appears Before All B's\. Easy Given a string `s` consisting of **only** the characters `'a'` and `'b'`, return `true` _if **every**_ `'a'` _appears before **every**_ `'b'` _in the string_. Otherwise, return `false`. **Example 1:** **Input:** s = "aaabbb" **Output:** true **Explanation:** The 'a's are at indices 0, 1, and 2, while the 'b's are at indices 3, 4, and 5. Hence, every 'a' appears before every 'b' and we return true. **Example 2:** **Input:** s = "abab" **Output:** false **Explanation:** There is an 'a' at index 2 and a 'b' at index 1. Hence, not every 'a' appears before every 'b' and we return false. **Example 3:** **Input:** s = "bbb" **Output:** true **Explanation:** There are no 'a's, hence, every 'a' appears before every 'b' and we return true. **Constraints:** * `1 <= s.length <= 100` * `s[i]` is either `'a'` or `'b'`.

  • Constructor Details

    • Solution

      public Solution()

  • Method Details

    • checkString

      public boolean checkString(String s)