Class Solution
java.lang.Object
g2301_2400.s2321_maximum_score_of_spliced_array.Solution
2321 - Maximum Score Of Spliced Array\.
Hard
You are given two **0-indexed** integer arrays `nums1` and `nums2`, both of length `n`.
You can choose two integers `left` and `right` where `0 <= left <= right < n` and **swap** the subarray `nums1[left...right]` with the subarray `nums2[left...right]`.
* For example, if `nums1 = [1,2,3,4,5]` and `nums2 = [11,12,13,14,15]` and you choose `left = 1` and `right = 2`, `nums1` becomes `[1, **12,13** ,4,5]` and `nums2` becomes `[11, **2,3** ,14,15]`.
You may choose to apply the mentioned operation **once** or not do anything.
The **score** of the arrays is the **maximum** of `sum(nums1)` and `sum(nums2)`, where `sum(arr)` is the sum of all the elements in the array `arr`.
Return _the **maximum possible score**_.
A **subarray** is a contiguous sequence of elements within an array. `arr[left...right]` denotes the subarray that contains the elements of `nums` between indices `left` and `right` ( **inclusive** ).
**Example 1:**
**Input:** nums1 = [60,60,60], nums2 = [10,90,10]
**Output:** 210
**Explanation:** Choosing left = 1 and right = 1, we have nums1 = [60, **90** ,60] and nums2 = [10, **60** ,10].
The score is max(sum(nums1), sum(nums2)) = max(210, 80) = 210.
**Example 2:**
**Input:** nums1 = [20,40,20,70,30], nums2 = [50,20,50,40,20]
**Output:** 220
**Explanation:** Choosing left = 3, right = 4, we have nums1 = [20,40,20, **40,20** ] and nums2 = [50,20,50, **70,30** ].
The score is max(sum(nums1), sum(nums2)) = max(140, 220) = 220.
**Example 3:**
**Input:** nums1 = [7,11,13], nums2 = [1,1,1]
**Output:** 31
**Explanation:** We choose not to swap any subarray.
The score is max(sum(nums1), sum(nums2)) = max(31, 3) = 31.
**Constraints:**
* `n == nums1.length == nums2.length`
*
1 <= n <= 105
* 1 <= nums1[i], nums2[i] <= 104-
Constructor Summary
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Solution
public Solution()
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Method Details
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maximumsSplicedArray
public int maximumsSplicedArray(int[] nums1, int[] nums2)
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