Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    828 - Count Unique Characters of All Substrings of a Given String\.

    Hard

    Let's define a function countUniqueChars(s) that returns the number of unique characters on s.

    • For example, calling countUniqueChars(s) if s = "LEETCODE" then "L", "T", "C", "O", "D" are the unique characters since they appear only once in s, therefore countUniqueChars(s) = 5.

    Given a string s, return the sum of countUniqueChars(t) where t is a substring of s. The test cases are generated such that the answer fits in a 32-bit integer.

    Notice that some substrings can be repeated so in this case you have to count the repeated ones too.

    Example 1:

    Input: s = "ABC"

    Output: 10

    Explanation: All possible substrings are: "A","B","C","AB","BC" and "ABC".

    Every substring is composed with only unique letters.

    Sum of lengths of all substring is 1 + 1 + 1 + 2 + 2 + 3 = 10

    Example 2:

    Input: s = "ABA"

    Output: 8

    Explanation: The same as example 1, except countUniqueChars("ABA") = 1.

    Example 3:

    Input: s = "LEETCODE"

    Output: 92

    Constraints:

    • <code>1 <= s.length <= 10<sup>5</sup></code>

    • s consists of uppercase English letters only.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer uniqueLetterString(String s)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait