Class Solution

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    public final class Solution
    
                        

    1356 - Sort Integers by The Number of 1 Bits\.

    Easy

    You are given an integer array arr. Sort the integers in the array in ascending order by the number of 1's in their binary representation and in case of two or more integers have the same number of 1's you have to sort them in ascending order.

    Return the array after sorting it.

    Example 1:

    Input: arr = 0,1,2,3,4,5,6,7,8

    Output: 0,1,2,4,8,3,5,6,7 Explantion: 0 is the only integer with 0 bits.

    1,2,4,8 all have 1 bit.

    3,5,6 have 2 bits.

    7 has 3 bits.

    The sorted array by bits is 0,1,2,4,8,3,5,6,7

    Example 2:

    Input: arr = 1024,512,256,128,64,32,16,8,4,2,1

    Output: 1,2,4,8,16,32,64,128,256,512,1024 Explantion: All integers have 1 bit in the binary representation, you should just sort them in ascending order.

    Constraints:

    • 1 <= arr.length <= 500

    • <code>0 <= arri<= 10<sup>4</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final IntArray sortByBits(IntArray arr)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait