Class Solution
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public final class Solution1386 - Cinema Seat Allocation\.
Medium
A cinema has
nrows of seats, numbered from 1 tonand there are ten seats in each row, labelled from 1 to 10 as shown in the figure above.Given the array
reservedSeatscontaining the numbers of seats already reserved, for example,reservedSeats[i] = [3,8]means the seat located in row 3 and labelled with 8 is already reserved.Return the maximum number of four-person groups you can assign on the cinema seats. A four-person group occupies four adjacent seats in one single row. Seats across an aisle (such as 3,3 and 3,4) are not considered to be adjacent, but there is an exceptional case on which an aisle split a four-person group, in that case, the aisle split a four-person group in the middle, which means to have two people on each side.
Example 1:
Input: n = 3, reservedSeats = \[\[1,2],1,3,1,8,2,6,3,1,3,10]
Output: 4
Explanation: The figure above shows the optimal allocation for four groups, where seats mark with blue are already reserved and contiguous seats mark with orange are for one group.
Example 2:
Input: n = 2, reservedSeats = \[\[2,1],1,8,2,6]
Output: 2
Example 3:
Input: n = 4, reservedSeats = \[\[4,3],1,4,4,6,1,7]
Output: 4
Constraints:
1 <= n <= 10^91 <= reservedSeats.length <= min(10*n, 10^4)reservedSeats[i].length == 21 <= reservedSeats[i][0] <= n1 <= reservedSeats[i][1] <= 10All
reservedSeats[i]are distinct.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegermaxNumberOfFamilies(Integer n, Array<IntArray> reservedSeats)-
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Method Detail
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maxNumberOfFamilies
final Integer maxNumberOfFamilies(Integer n, Array<IntArray> reservedSeats)
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