Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    1606 - Find Servers That Handled Most Number of Requests\.

    Hard

    You have k servers numbered from 0 to k-1 that are being used to handle multiple requests simultaneously. Each server has infinite computational capacity but cannot handle more than one request at a time. The requests are assigned to servers according to a specific algorithm:

    • The <code>i<sup>th</sup></code> (0-indexed) request arrives.

    • If all servers are busy, the request is dropped (not handled at all).

    • If the <code>(i % k)<sup>th</sup></code> server is available, assign the request to that server.

    • Otherwise, assign the request to the next available server (wrapping around the list of servers and starting from 0 if necessary). For example, if the <code>i<sup>th</sup></code> server is busy, try to assign the request to the <code>(i+1)<sup>th</sup></code> server, then the <code>(i+2)<sup>th</sup></code> server, and so on.

    You are given a strictly increasing array arrival of positive integers, where arrival[i] represents the arrival time of the <code>i<sup>th</sup></code> request, and another array load, where load[i] represents the load of the <code>i<sup>th</sup></code> request (the time it takes to complete). Your goal is to find the busiest server(s). A server is considered busiest if it handled the most number of requests successfully among all the servers.

    Return a list containing the IDs (0-indexed) of the busiest server(s). You may return the IDs in any order.

    Example 1:

    Input: k = 3, arrival = 1,2,3,4,5, load = 5,2,3,3,3

    Output: 1

    Explanation:

    All of the servers start out available.

    The first 3 requests are handled by the first 3 servers in order.

    Request 3 comes in. Server 0 is busy, so it's assigned to the next available server, which is 1.

    Request 4 comes in. It cannot be handled since all servers are busy, so it is dropped.

    Servers 0 and 2 handled one request each, while server 1 handled two requests. Hence server 1 is the busiest server.

    Example 2:

    Input: k = 3, arrival = 1,2,3,4, load = 1,2,1,2

    Output: 0

    Explanation:

    The first 3 requests are handled by first 3 servers.

    Request 3 comes in. It is handled by server 0 since the server is available.

    Server 0 handled two requests, while servers 1 and 2 handled one request each. Hence server 0 is the busiest server.

    Example 3:

    Input: k = 3, arrival = 1,2,3, load = 10,12,11

    Output: 0,1,2

    Explanation: Each server handles a single request, so they are all considered the busiest.

    Constraints:

    • <code>1 <= k <= 10<sup>5</sup></code>

    • <code>1 <= arrival.length, load.length <= 10<sup>5</sup></code>

    • arrival.length == load.length

    • <code>1 <= arrivali, loadi<= 10<sup>9</sup></code>

    • arrival is strictly increasing.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final List<Integer> busiestServers(Integer k, IntArray arrival, IntArray load)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait