2124 - Check if All A's Appears Before All B's\.

Easy

Given a string s consisting of only the characters 'a' and 'b', return true if every 'a' appears before every 'b' in the string. Otherwise, return false.

Example 1:

Input: s = "aaabbb"

Output: true

Explanation:

The 'a's are at indices 0, 1, and 2, while the 'b's are at indices 3, 4, and 5.

Hence, every 'a' appears before every 'b' and we return true.

Example 2:

Input: s = "abab"

Output: false

Explanation:

There is an 'a' at index 2 and a 'b' at index 1.

Hence, not every 'a' appears before every 'b' and we return false.

Example 3:

Input: s = "bbb"

Output: true

Explanation: There are no 'a's, hence, every 'a' appears before every 'b' and we return true.

Constraints:

• 1 <= s.length <= 100

• s[i] is either 'a' or 'b'.