Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    2278 - Percentage of Letter in String\.

    Easy

    Given a string s and a character letter, return the percentage of characters in s that equal letter rounded down to the nearest whole percent.

    Example 1:

    Input: s = "foobar", letter = "o"

    Output: 33

    Explanation:

    The percentage of characters in s that equal the letter 'o' is 2 / 6 \* 100% = 33% when rounded down, so we return 33.

    Example 2:

    Input: s = "jjjj", letter = "k"

    Output: 0

    Explanation:

    The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.

    Constraints:

    • 1 <= s.length <= 100

    • s consists of lowercase English letters.

    • letter is a lowercase English letter.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer percentageLetter(String s, Character letter)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait