Class Solution
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- All Implemented Interfaces:
public final class Solution2482 - Difference Between Ones and Zeros in Row and Column\.
Medium
You are given a 0-indexed
m x nbinary matrixgrid.A 0-indexed
m x ndifference matrixdiffis created with the following procedure:Let the number of ones in the <code>i<sup>th</sup></code> row be <code>onesRow<sub>i</sub></code>.
Let the number of ones in the <code>j<sup>th</sup></code> column be <code>onesCol<sub>j</sub></code>.
Let the number of zeros in the <code>i<sup>th</sup></code> row be <code>zerosRow<sub>i</sub></code>.
Let the number of zeros in the <code>j<sup>th</sup></code> column be <code>zerosCol<sub>j</sub></code>.
<code>diffj = onesRow<sub>i</sub> + onesCol<sub>j</sub> - zerosRow<sub>i</sub> - zerosCol<sub>j</sub></code>
Return the difference matrix
diff.Example 1:
Input: grid = \[\[0,1,1],1,0,1,0,0,1]
Output: [0,0,4,0,0,4,-2,-2,2]
Explanation:
diff0 = <code>onesRow<sub>0</sub> + onesCol<sub>0</sub> - zerosRow<sub>0</sub> - zerosCol<sub>0</sub></code> = 2 + 1 - 1 - 2 = 0
diff1 = <code>onesRow<sub>0</sub> + onesCol<sub>1</sub> - zerosRow<sub>0</sub> - zerosCol<sub>1</sub></code> = 2 + 1 - 1 - 2 = 0
diff2 = <code>onesRow<sub>0</sub> + onesCol<sub>2</sub> - zerosRow<sub>0</sub> - zerosCol<sub>2</sub></code> = 2 + 3 - 1 - 0 = 4
diff0 = <code>onesRow<sub>1</sub> + onesCol<sub>0</sub> - zerosRow<sub>1</sub> - zerosCol<sub>0</sub></code> = 2 + 1 - 1 - 2 = 0
diff1 = <code>onesRow<sub>1</sub> + onesCol<sub>1</sub> - zerosRow<sub>1</sub> - zerosCol<sub>1</sub></code> = 2 + 1 - 1 - 2 = 0
diff2 = <code>onesRow<sub>1</sub> + onesCol<sub>2</sub> - zerosRow<sub>1</sub> - zerosCol<sub>2</sub></code> = 2 + 3 - 1 - 0 = 4
diff0 = <code>onesRow<sub>2</sub> + onesCol<sub>0</sub> - zerosRow<sub>2</sub> - zerosCol<sub>0</sub></code> = 1 + 1 - 2 - 2 = -2
diff1 = <code>onesRow<sub>2</sub> + onesCol<sub>1</sub> - zerosRow<sub>2</sub> - zerosCol<sub>1</sub></code> = 1 + 1 - 2 - 2 = -2
diff2 = <code>onesRow<sub>2</sub> + onesCol<sub>2</sub> - zerosRow<sub>2</sub> - zerosCol<sub>2</sub></code> = 1 + 3 - 2 - 0 = 2
Example 2:
Input: grid = \[\[1,1,1],1,1,1]
Output: [5,5,5,5,5,5]
Explanation:
diff0 = onesRow<sub>0</sub> + onesCol<sub>0</sub> - zerosRow<sub>0</sub> - zerosCol<sub>0</sub> = 3 + 2 - 0 - 0 = 5
diff1 = onesRow<sub>0</sub> + onesCol<sub>1</sub> - zerosRow<sub>0</sub> - zerosCol<sub>1</sub> = 3 + 2 - 0 - 0 = 5
diff2 = onesRow<sub>0</sub> + onesCol<sub>2</sub> - zerosRow<sub>0</sub> - zerosCol<sub>2</sub> = 3 + 2 - 0 - 0 = 5
diff0 = onesRow<sub>1</sub> + onesCol<sub>0</sub> - zerosRow<sub>1</sub> - zerosCol<sub>0</sub> = 3 + 2 - 0 - 0 = 5
diff1 = onesRow<sub>1</sub> + onesCol<sub>1</sub> - zerosRow<sub>1</sub> - zerosCol<sub>1</sub> = 3 + 2 - 0 - 0 = 5
diff2 = onesRow<sub>1</sub> + onesCol<sub>2</sub> - zerosRow<sub>1</sub> - zerosCol<sub>2</sub> = 3 + 2 - 0 - 0 = 5
Constraints:
m == grid.lengthn == grid[i].length<code>1 <= m, n <= 10<sup>5</sup></code>
<code>1 <= m * n <= 10<sup>5</sup></code>
grid[i][j]is either0or1.