Class Solution

  • All Implemented Interfaces:

    
    public final class Solution
    
                        

    2507 - Smallest Value After Replacing With Sum of Prime Factors\.

    Medium

    You are given a positive integer n.

    Continuously replace n with the sum of its prime factors.

    • Note that if a prime factor divides n multiple times, it should be included in the sum as many times as it divides n.

    Return the smallest value n will take on.

    Example 1:

    Input: n = 15

    Output: 5

    Explanation: Initially, n = 15.

    15 = 3 \* 5, so replace n with 3 + 5 = 8.

    8 = 2 \* 2 \* 2, so replace n with 2 + 2 + 2 = 6.

    6 = 2 \* 3, so replace n with 2 + 3 = 5.

    5 is the smallest value n will take on.

    Example 2:

    Input: n = 3

    Output: 3

    Explanation: Initially, n = 3. 3 is the smallest value n will take on.

    Constraints:

    • <code>2 <= n <= 10<sup>5</sup></code>

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description
    • Field Summary

      Fields 
      Modifier and Type Field Description
    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()
    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description
    • Method Summary

      Modifier and Type Method Description
      final Integer smallestValue(Integer n)
      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait