Class Solution
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public final class Solution2552 - Count Increasing Quadruplets\.
Hard
Given a 0-indexed integer array
numsof sizencontaining all numbers from1ton, return the number of increasing quadruplets.A quadruplet
(i, j, k, l)is increasing if:0 <= i < j < k < l < n, andnums[i] < nums[k] < nums[j] < nums[l].
Example 1:
Input: nums = 1,3,2,4,5
Output: 2
Explanation:
When i = 0, j = 1, k = 2, and l = 3, numsi< numsk< numsj< numsl.
When i = 0, j = 1, k = 2, and l = 4, numsi< numsk< numsj< numsl. There are no other quadruplets, so we return 2.
Example 2:
Input: nums = 1,2,3,4
Output: 0
Explanation:
There exists only one quadruplet with i = 0, j = 1, k = 2, l = 3, but since numsj< numsk, we return 0.
Constraints:
4 <= nums.length <= 40001 <= nums[i] <= nums.lengthAll the integers of
numsare unique.numsis a permutation.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final LongcountQuadruplets(IntArray nums)-
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Method Detail
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countQuadruplets
final Long countQuadruplets(IntArray nums)
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