Class Solution
-
- All Implemented Interfaces:
public final class Solution828 - Count Unique Characters of All Substrings of a Given String.
Hard
Let's define a function
countUniqueChars(s)that returns the number of unique characters ons.For example, calling
countUniqueChars(s)ifs = "LEETCODE"then"L","T","C","O","D"are the unique characters since they appear only once ins, thereforecountUniqueChars(s) = 5.
Given a string
s, return the sum ofcountUniqueChars(t)wheretis a substring ofs. The test cases are generated such that the answer fits in a 32-bit integer.Notice that some substrings can be repeated so in this case you have to count the repeated ones too.
Example 1:
Input: s = "ABC"
Output: 10
Explanation: All possible substrings are: "A","B","C","AB","BC" and "ABC".
Every substring is composed with only unique letters.
Sum of lengths of all substring is 1 + 1 + 1 + 2 + 2 + 3 = 10
Example 2:
Input: s = "ABA"
Output: 8
Explanation: The same as example 1, except
countUniqueChars("ABA") = 1.Example 3:
Input: s = "LEETCODE"
Output: 92
Constraints:
<code>1 <= s.length <= 10<sup>5</sup></code>
sconsists of uppercase English letters only.
-
-
Constructor Summary
Constructors Constructor Description Solution()
-
Method Summary
Modifier and Type Method Description final IntegeruniqueLetterString(String s)-
-
Method Detail
-
uniqueLetterString
final Integer uniqueLetterString(String s)
-
-
-
-