Class Solution
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public final class Solution2278 - Percentage of Letter in String.
Easy
Given a string
sand a characterletter, return the percentage of characters insthat equalletterrounded down to the nearest whole percent.Example 1:
Input: s = "foobar", letter = "o"
Output: 33
Explanation:
The percentage of characters in s that equal the letter 'o' is 2 / 6 \* 100% = 33% when rounded down, so we return 33.
Example 2:
Input: s = "jjjj", letter = "k"
Output: 0
Explanation:
The percentage of characters in s that equal the letter 'k' is 0%, so we return 0.
Constraints:
1 <= s.length <= 100sconsists of lowercase English letters.letteris a lowercase English letter.
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Constructor Summary
Constructors Constructor Description Solution()
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Method Summary
Modifier and Type Method Description final IntegerpercentageLetter(String s, Character letter)-
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Method Detail
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percentageLetter
final Integer percentageLetter(String s, Character letter)
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