Class Solution
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public final class Solution2662 - Minimum Cost of a Path With Special Roads.
Medium
You are given an array
startwherestart = [startX, startY]represents your initial position(startX, startY)in a 2D space. You are also given the arraytargetwheretarget = [targetX, targetY]represents your target position(targetX, targetY).The cost of going from a position
(x1, y1)to any other position in the space(x2, y2)is|x2 - x1| + |y2 - y1|.There are also some special roads. You are given a 2D array
specialRoadswhere <code>specialRoadsi = x1<sub>i</sub>, y1<sub>i</sub>, x2<sub>i</sub>, y2<sub>i</sub>, cost<sub>i</sub></code> indicates that the <code>i<sup>th</sup></code> special road can take you from <code>(x1<sub>i</sub>, y1<sub>i</sub>)</code> to <code>(x2<sub>i</sub>, y2<sub>i</sub>)</code> with a cost equal to <code>cost<sub>i</sub></code>. You can use each special road any number of times.Return the minimum cost required to go from
(startX, startY)to(targetX, targetY).Example 1:
Input: start = 1,1, target = 4,5, specialRoads = \[\[1,2,3,3,2],3,4,4,5,1]
Output: 5
Explanation: The optimal path from (1,1) to (4,5) is the following:
(1,1) -> (1,2). This move has a cost of |1 - 1| + |2 - 1| = 1.
(1,2) -> (3,3). This move uses the first special edge, the cost is 2.
(3,3) -> (3,4). This move has a cost of |3 - 3| + |4 - 3| = 1.
(3,4) -> (4,5). This move uses the second special edge, the cost is 1.
So the total cost is 1 + 2 + 1 + 1 = 5.
It can be shown that we cannot achieve a smaller total cost than 5.
Example 2:
Input: start = 3,2, target = 5,7, specialRoads = \[\[3,2,3,4,4],3,3,5,5,5,3,4,5,6,6]
Output: 7
Explanation: It is optimal to not use any special edges and go directly from the starting to the ending position with a cost |5 - 3| + |7 - 2| = 7.
Constraints:
start.length == target.length == 2<code>1 <= startX <= targetX <= 10<sup>5</sup></code>
<code>1 <= startY <= targetY <= 10<sup>5</sup></code>
1 <= specialRoads.length <= 200specialRoads[i].length == 5<code>startX <= x1<sub>i</sub>, x2<sub>i</sub><= targetX</code>
<code>startY <= y1<sub>i</sub>, y2<sub>i</sub><= targetY</code>
<code>1 <= cost<sub>i</sub><= 10<sup>5</sup></code>