2903 - Find Indices With Index and Value Difference I.

Easy

You are given a 0-indexed integer array nums having length n, an integer indexDifference, and an integer valueDifference.

Your task is to find two indices i and j, both in the range [0, n - 1], that satisfy the following conditions:

• abs(i - j) >= indexDifference, and

• abs(nums[i] - nums[j]) >= valueDifference

Return an integer array answer, where answer = [i, j] if there are two such indices, and answer = [-1, -1] otherwise. If there are multiple choices for the two indices, return any of them.

Note: i and j may be equal.

Example 1:

Input: nums = 5,1,4,1, indexDifference = 2, valueDifference = 4

Output: 0,3

Explanation: In this example, i = 0 and j = 3 can be selected.

abs(0 - 3) >= 2 and abs(nums0 - nums3) >= 4.

Hence, a valid answer is 0,3. 3,0 is also a valid answer.

Example 2:

Input: nums = 2,1, indexDifference = 0, valueDifference = 0

Output: 0,0

Explanation: In this example, i = 0 and j = 0 can be selected.

abs(0 - 0) >= 0 and abs(nums0 - nums0) >= 0.

Hence, a valid answer is 0,0.

Other valid answers are 0,1, 1,0, and 1,1.

Example 3:

Input: nums = 1,2,3, indexDifference = 2, valueDifference = 4

Output: -1,-1

Explanation: In this example, it can be shown that it is impossible to find two indices that satisfy both conditions. Hence, -1,-1 is returned.

Constraints:

• 1 <= n == nums.length <= 100

• 0 <= nums[i] <= 50

• 0 <= indexDifference <= 100

• 0 <= valueDifference <= 50