Package g3001_3100.s3083_existence_of_a_substring_in_a_string_and_its_reverse

Class Solution

  • All Implemented Interfaces:
    
public final class Solution

    3083 - Existence of a Substring in a String and Its Reverse.

    Easy

    Given a string s, find any substring of length 2 which is also present in the reverse of s.

    Return true if such a substring exists, and false otherwise.

    Example 1:

    Input: s = "leetcode"

    Output: true

    Explanation: Substring "ee" is of length 2 which is also present in reverse(s) == "edocteel".

    Example 2:

    Input: s = "abcba"

    Output: true

    Explanation: All of the substrings of length 2 "ab", "bc", "cb", "ba" are also present in reverse(s) == "abcba".

    Example 3:

    Input: s = "abcd"

    Output: false

    Explanation: There is no substring of length 2 in s, which is also present in the reverse of s.

    Constraints:

    • 1 <= s.length <= 100

    • s consists only of lowercase English letters.

    • Nested Class Summary

      Nested Classes 
      Modifier and Type Class Description

    • Field Summary

      Fields 
      Modifier and Type Field Description

    • Constructor Summary

      Constructors 
      Constructor Description
      Solution()

    • Enum Constant Summary

      Enum Constants 
      Enum Constant Description

    • Method Summary

      Modifier and Type Method Description
      final Boolean isSubstringPresent(String s)

      • Methods inherited from class java.lang.Object

        clone, equals, finalize, getClass, hashCode, notify, notifyAll, toString, wait, wait, wait